# Which Pair Of Complex Numbers Has A Real Number Product – When Graphed, Which Parabola Opens Downward?

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## Which pair of complex numbers has a real number product

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A complicated quantity z can thus be recognized with an ordered pair of actual numbers, which in flip could also be interpreted as coordinates of some extent in a two-dimensional space. The most rapid area is the Euclidean aircraft with appropriate coordinates, which is then referred to as complicated aircraft or Argand diagram,[9][b][10] named after Jean-Robert Argand. Another outstanding area on which the coordinates could also be projected is the two-dimensional floor of a sphere, which is then referred to as Riemann sphere.

Cartesian complicated plane[edit]

The definition of the complicated numbers involving two arbitrary actual values all of a sudden suggests using Cartesian coordinates within the complicated plane. The horizontal (real) axis is usually used to exhibit the actual part, with growing values to the right, and the imaginary element marks the vertical (imaginary) axis, with growing values upwards.

A charted quantity could also be seen both because the coordinatized level or as a place vector from the origin to this point. The coordinate values of a posh quantity z can therefore be expressed in its Cartesian, rectangular, or algebraic form.

Notably, the operations of addition and multiplication tackle a totally pure geometric character, when complicated numbers are seen as place vectors: addition corresponds to vector addition, whereas multiplication (see below) corresponds to multiplying their magnitudes and including the angles they make with the actual axis. Viewed on this way, the multiplication of a posh quantity via i corresponds to rotating the location vector counterclockwise by means of 1 / 4 flip (90°) concerning the origin—a reality which may be expressed algebraically as follows:

Polar complicated aircraft [edit]

Modulus and argument[edit]

An various choice for coordinates within the complicated aircraft is the polar coordinate formulation that makes use of the space of the purpose z from the origin (O), and the attitude subtended between the wonderful actual axis and the road phase Oz in a counterclockwise sense. This results within the polar form

of a posh number, the place r is absolutely the worth of z, and is the argument of z.

The absolute worth (or modulus or magnitude) of a posh quantity z = x + yi is[11]

By Pythagoras’ theorem, absolutely the worth of a posh quantity is the space to the origin of the purpose representing the complicated quantity in the complicated plane.

The argument of z (in many purposes referred to because the “phase” φ)[10] is the attitude of the radius Oz with the effective actual axis, and is written as arg z. As with the modulus, the argument could be chanced on from the oblong type x + yi[12]—by making use of the inverse tangent to the quotient of imaginary-by-real parts. By utilizing a half-angle identity, a single department of the arctan suffices to conceal the variability (−π, π] of the arg-function, and avoids a extra refined case-by-case analysis

Normally, as given above, the principal worth within the interval (−π, π] is chosen. If the arg worth is negative, values within the variability (−π, π] or [0, 2π) might be acquired via including 2π. The worth of φ is expressed in radians on this article. It can amplify via any integer a number of of 2π and nonetheless give the identical angle, seen as subtended by means of the rays of the advantageous actual axis and from the origin by way of z. Hence, the arg position is usually regarded as multivalued. The polar angle for the complicated quantity zero is indeterminate, however arbitrary selection of the polar angle zero is common.

The worth of φ equals the results of atan2:

Together, r and φ give differently of representing complicated numbers, the polar form, because the mixture of modulus and argument completely specify the location of some extent on the plane. Recovering the unique rectangular co-ordinates from the polar type is completed via the components referred to as trigonometric form

Using Euler’s components this may be written as

Using the cis function, that is usually abbreviated to

In angle notation, sometimes utilized in electronics to symbolize a phasor with amplitude r and part φ, it’s written as[13]

Complex graphs[edit]

When visualizing complicated functions, each a posh enter and output are needed. Because every complicated quantity is represented in two dimensions, visually graphing a posh position would require the notion of a 4 dimensional space, which is feasible solely in projections. Because of this, alternative methods of visualizing complicated purposes have been designed.

In area coloring the output dimensions are represented via colour and brightness, respectively. Each level within the complicated aircraft as area is ornated, usually with colour representing the argument of the complicated number, and brightness representing the magnitude. Dark spots mark moduli close to zero, brighter spots are farther away from the origin, the gradation could also be discontinuous, however is assumed as monotonous. The colours sometimes differ in steps of π/3 for zero to 2π from red, yellow, green, cyan, blue, to magenta. These plots are referred to as colour wheel graphs. This gives an easy solution to visualise the purposes with out dropping information. The photograph exhibits zeros for ±1, (2 + i) and poles at

## What is the absolute value of the complex number negative 4 minus startroot 2 endroot i?

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Being one in all probably the essential equations in mathematics, Euler’s components definitely has its justifiable proportion of fascinating purposes in several topics. These include, amongst others:

- The well-known Euler’s identity
- The exponential type of complicated numbers
- Alternate definitions of trigonometric and hyperbolic functions
- Generalization of exponential and logarithmic purposes to complicated numbers
- Alternate proofs of de Moivre’s theorem and trigonometric additive identities

Euler’s Identity

Euler’s id is usually seen to be probably the most lovely equation in mathematics. It is written as

where it showcases 5 of probably the principal constants in mathematics. These are:

- The additive id $0$
- The harmony $1$
- The Pi fixed $\pi$ (ratio of a circle’s circumference to its diameter)
- The base of pure logarithm $e$
- The imaginary unit $i$

Among these, three styles of numbers are represented: integers, irrational numbers and imaginary numbers. Three of the essential mathematical operations are additionally represented: addition, multiplication and exponentiation.

We receive Euler’s id via means of beginning with Euler’s components \[ e^{ix} = \cos x + i \sin x \] and by atmosphere $x = \pi$ and sending the next $-1$ to the left-hand side. The intermediate variety \[ e^{i \pi} = -1 \] is widespread within the context of trigonometric unit circle within the complicated plane: it corresponds to the purpose on the unit circle whose angle with respect to the wonderful actual axis is $\pi$.

Complex Numbers in Exponential Form

At this point, we already know that a posh quantity $z$ could be expressed in Cartesian coordinates as $x + iy$, the place $x$ and $y$ are respectively the actual element and the imaginary a element of $z$.

Indeed, the identical complicated quantity may even be expressed in polar coordinates as $r(\cos \theta + i \sin \theta)$, the place $r$ is the magnitude of its distance to the origin, and $\theta$ is its angle with respect to the effective actual axis.

But it doesn’t finish there: because of Euler’s formula, each complicated quantity can now be expressed as a posh exponential as follows:

$z = r(\cos \theta + i \sin \theta) = r e^{i \theta}$

where $r$ and $\theta$ are the identical numbers as before.

To go from $(x, y)$ to $(r, \theta)$, we use the formulation \begin{align*} r & = \sqrt{x^2 + y^2} \\[4px] \theta & = \operatorname{atan2}(y, x) \end{align*} (where $\operatorname{atan2}(y, x)$ is the two-argument arctangent position with $\operatorname{atan2}(y, x) = \arctan (\frac{y}{x})$ every time $x>0$.)

Conversely, to go from $(r, \theta)$ to $(x, y)$, we use the formulas: \begin{align*} x & = r \cos \theta \\[4px] y & = r \sin \theta \end{align*} The exponential type of complicated numbers additionally makes multiplying complicated numbers a lot simpler — very similar to the identical approach rectangular coordinates make addition easier. For example, given two complicated numbers $z_1 = r_1 e^{i \theta_1}$ and $z_2 = r_2 e^{i \theta_2}$, we will now multiply them collectively as follows: \begin{align*} z_1 z_2 & = r_1 e^{i \theta_1} \cdot r_2 e^{i \theta_2} \\ & = r_1 r_2 e^{i(\theta_1 + \theta_2)} \end{align*} In the identical spirit, we will additionally divide the identical two numbers as follows: \begin{align*} \frac{z1}{z2} & = \frac{r_1 e^{i \theta_1}}{r_2 e^{i \theta_2}} \\ & = \frac{r_1}{r_2} e^{i (\theta_{1}-\theta_2)} \end{align*}

To be sure, these do presuppose houses of exponent reminiscent of $e^{z_1+z_2}=e^{z_1} e^{z_2}$ and $e^{-z_1} = \frac{1}{e^{z_1}}$, which as an instance might be established by means of means of increasing the facility collection of $e^{z_1}$, $e^{-z_1}$ and $e^{z_2}$.

Had we used the oblong $x + iy$ notation instead, the identical division would have required multiplying by the complicated conjugate within the numerator and denominator. With the polar coordinates, the state of affairs would have been the identical (save maybe worse).

If anything, the exponential type positive makes it simpler to see that multiplying two complicated numbers is de facto the identical as multiplying magnitudes and including angles, and that dividing two complicated numbers is basically the identical as dividing magnitudes and subtracting angles.

Alternate Definitions of Key Functions

Euler’s formulation additionally can be used to supply alternate definitions to key purposes similar to the complicated exponential function, trigonometric purposes equivalent to sine, cosine and tangent, and their hyperbolic counterparts. It may even be used to determine the connection between a few of those purposes as well.

Complex Exponential Function

To begin, recall that Euler’s components states that \[ e^{ix} = \cos x + i \sin x \] If the components is assumed to carry for actual $x$ only, then the exponential position is barely outlined as much as the imaginary numbers. However, we will additionally develop the exponential position to incorporate all complicated numbers — via following a totally straightforward trick:

$e^{z} = e^{x+iy} \, (= e^x e^{iy}) \overset{df}{=} e^x (\cos y + i \sin y)$

Here, we’re not essentially assuming that the additive belongings for exponents holds (which it does), however that the primary and the final expression are equal.

In different words, the exponential of the complicated quantity $x+iy$ is just the complicated quantity whose magnitude is $e^x$ and whose angle is $y$. Interestingly, this suggests that complicated exponential in reality maps vertical strains to circles. Here’s an animation as an instance the point:

Trigonometric Functions

Apart from extending the area of exponential function, we will additionally use Euler’s components to derive an identical equation for the reverse angle $-x$: \[ e^{-ix} = \cos x-i \sin x \] This equation, collectively with Euler’s components itself, represent a formulation of equations from which we will isolate each the sine and cosine functions.

For example, by way of subtracting the $e^{-ix}$ equation from the $e^{ix}$ equation, the cosines cancel out and after dividing via $2i$, we get the complicated exponential type of the sine function:

$\sin x = \dfrac{e^{ix}-e^{-ix}}{2i}$

Similarly, via including the 2 equations together, the sines cancel out and after dividing by means of $2$, we get the complicated exponential type of the cosine function:

$\cos x = \dfrac{e^{ix} + e^{-ix}}{2}$

To be sure, here’s a video illustrating the identical derivations in additional detail.

On the different hand, the tangent position is outlined to be $\frac{\sin x}{\cos x}$, so in phrases of complicated exponentials, it becomes:

$\tan x = \dfrac{e^{ix}-e^{-ix}}{i(e^{ix} + e^{-ix})}$

If Euler’s components is confirmed to carry for all complicated numbers (as we did within the proof via energy series), then the identical can be true for these three formulation as well. Their presence permits us to exchange freely between trigonometric purposes and sophisticated exponentials, which is an enormous plus when it involves calculating derivatives and integrals.

Hyperbolic Functions

In addition to trigonometric functions, hyperbolic purposes are but one more magnificence of purposes that may be outlined in phrases of complicated exponentials. In fact, it’s via way of this connection we will determine a hyperbolic position with its trigonometric counterpart.

For example, by beginning with complicated sine and sophisticated cosine and plugging in $iz$ (and making use of the details that $i^2 = -1$ and $1/i = -i$), we have: \begin{align*} \sin iz & = \frac{e^{i(iz)}-e^{-i(iz)}}{2i} \\ & = \frac{e^{-z}-e^{z}}{2i} \\ & = i \left(\frac{e^z-e^{-z}}{2}\right) \\ & = i \sinh z \end{align*} \begin{align*} \cos iz & = \frac{e^{i(iz)}+e^{-i(iz)}}{2} \\ & = \frac{e^z + e^{-z}}{2} \\ & = \cosh z \end{align*} From these, we will additionally plug in $iz$ into complicated tangent and get: \[ \tan (iz) = \frac{\sin iz}{\cos iz} = \frac{i \sinh z}{\cosh z} = i \tanh z \] In short, this suggests that we will now outline hyperbolic purposes in phrases of trigonometric purposes as follows:

\begin{align*} \sinh z & = \frac{\sin iz}{i} \\[4px] \cosh z & = \cos iz \\[4px] \tanh z & = \frac{\tan iz}{i} \end{align*}

But then, these aren’t the one purposes we will present new definitions to. In fact, the complicated logarithm and the overall complicated exponential are two different periods of purposes we will outline — as a results of Euler’s formula.

Complex Logarithm and General Complex Exponential

The logarithm of a posh quantity behaves in a weird method in comparison to the logarithm of an actual number. More specifically, it has an unlimited variety of values rather than one.

To see how, we begin with the definition of logarithmic position because the inverse of exponential function. That is: \begin{align*} e^{\ln z} & = z & \ln (e^z) & = z \end{align*} Furthermore, we additionally know that for any pair of complicated numbers $z_1$ and $z_2$, the additive belongings for exponents holds: \[ e^{z_1} e^{z_2} = e^{z_1+z_2} \] Thus, when a non-zero complicated quantity is expressed as an exponential, we have got that: \[ z = |z| e^{i\phi} = e^{\ln |z|} e^{i\phi} = e^{\ln |z| + i\phi} \] the place $|z|$ is the magnitude of $z$ and $\phi$ is the attitude of $z$ from the high-quality actual axis. And since logarithm is just the exponent of a quantity when it’s raised to $e$, the subsequent definition is in order: \[ \ln z = \ln |z| + i\phi \] At first, this looks like a strong approach of defining the complicated logarithm. However, a re-evaluation exhibits that the logarithm outlined this type can assume an unlimited variety of values — because of the very incontrovertible reality that $\phi$ may even be chosen to be every different variety of the shape $\phi + 2\pi k$ (where $k$ is an integer).

For example, we’ve observed from earlier that $e^{0}=1$ and $e^{2\pi i}=1$. This skill one might outline the logarithm of $1$ to be each $0$ and $2\pi i$ — or any variety of the shape $2\pi ki$ for that matter (where $k$ is an integer).

To clear up this conundrum, two separate approaches are often used. The first method is to only take into account the complicated logarithm as a multi-valued function. That is, a position that maps every enter to a hard and fast of values. One option to realize that is to outline $\ln z$ as follows: \[ \{\ln |z| + i(\phi + 2\pi k) \} \] the place $-\pi < \phi \le \pi$ and $k$ is an integer. Here, the clause $-\pi < \phi \le \pi$ has the impact of proscribing the attitude of $z$ to just one candidate. Because of that, the $\phi$ outlined this type is normally referred to as the principal angle of $z$.

The second approach, which is arguably extra elegant, is to only outline the complicated logarithm of $z$ in order that $\phi$ is the principal angle of $z$. With that understanding, the unique definition then turns into well-defined:

$\ln z = \ln |z| + i\phi$

For example, beneath this new rule, we’d have that $\ln 1 = 0$ and $\ln i = \ln \left( e^{i\frac{\pi}{2}} \right) = i\frac{\pi}{2}$. No longer are we caught with the difficulty of periodicity of angles!

However, with the restriction that $-\pi < \phi \le \pi$, the variability of complicated logarithm is now lowered to the oblong area $-\pi < y \le \pi$ (i.e., the principal branch). And if we’d like to maintain the inverse courting between logarithm and exponential, we’d additionally have to do the identical to the area of exponential position as well.

But then, since the complicated logarithm is now well-defined, we will additionally outline many different issues based mostly on it with out operating into ambiguity. One such instance might be the overall complicated exponential (with a non-zero base $a$), which may be outlined as follows:

$a^z = e^{\ln (a^z)} \overset{df}{=} e^{z \ln a}$

Here, we’re not assuming that the facility rule for logarithm holds (because it doesn’t), however that the primary and the final expression are equal.

For example, utilizing the overall complicated exponential as outlined above, we will now get a way of what $i^i$ truthfully means: \begin{align*} i^i & = e^{i \ln i} \\ & = e^{i \frac{\pi}{2}i} \\ & = e^{-\frac{\pi}{2}} \\ & \approx 0.208 \end{align*}

Alternate Proofs of De Moivre’s Theorem and Trigonometric Additive Identities

The theorem referred to as de Moivre’s theorem states that

$(\cos x + i \sin x)^n = \cos nx + i \sin nx$

where $x$ is an actual quantity and $n$ is an integer. By default, this will be proven to be true via means of induction (through using some trigonometric identities), however with the assistance of Euler’s formula, a far easier proof now exists.

To begin, recall that the multiplicative belongings for exponents states that \[ (e^z)^k = e^{zk} \] While this belongings is usually not true for complicated numbers, it does preserve within the particular case the place $k$ is an integer. Indeed, it’s not arduous to see that on this case, the maths in reality boils right down to repeated purposes of the additive belongings for exponents.

And with that settled, we will then simply derive de Moivre’s theorem as follows: \[ (\cos x + i \sin x)^n = {(e^{ix})}^n = e^{i nx} = \cos nx + i \sin nx \] In practice, this theorem is usually used discover the roots of a posh number, and to acquire closed-form expressions for $\sin nx$ and $\cos nx$. It does so via decreasing purposes raised to excessive powers to straightforward trigonometric purposes — in order that calculations might be performed with ease.

In fact, de Moivre’s theorem isn’t the one theorem whose proof could be simplified as a results of Euler’s formula. Other identities, equivalent to the additive identities for $\sin (x+y)$ and $\cos (x+y)$, additionally take pleasure in that impact as well.

Indeed, we already know that for all actual $x$ and $y$: \begin{align*} \cos (x+y) + i \sin (x+y) & = e^{i(x+y)} \\ & = e^{ix} \cdot e^{iy} \\ & = ( \cos x + i \sin x ) (\cos y + i \sin y) \\ & = (\cos x \cos y-\sin x \sin y) \\[1px] & \; \; + i(\sin x \cos y + \cos x \sin y) \end{align*} Once there, equating the actual and imaginary elements on each side then yields the famed identities we have been searching for:

\begin{align*} \cos (x+y) & = \cos x \cos y-\sin x \sin y \\[4px] \sin (x+y) & = \sin x \cos y + \cos x \sin y \end{align*}

## What is the additive identity of the complex number 14 + 5i?

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The houses of complicated numbers are listed below:

- The addition of two conjugate complicated numbers will end in an actual number
- The multiplication of two conjugate complicated quantity may additionally end in an actual number
- If x and y are the actual numbers and x+yi =0, then x =0 and y =0
- If p, q, r, and s are the actual numbers and p+qi = r+si, then p = r, and q=s
- The complicated quantity obeys the commutative regulation of addition and multiplication.

- The complicated quantity obeys the associative regulation of addition and multiplication.

(z1+z2) +z3 = z1 + (z2+z3)

(z1.z2).z3 = z1.(z2.z3)

- The complicated quantity obeys the distributive law

z1.(z2+z3) = z1.z2 + z1.z3

- If the sum of two complicated quantity is real, and in addition the product of two complicated quantity can additionally be real, then these complicated numbers are conjugate to every other.
- For any two complicated numbers, say z1 and z2, then |z1+z2| ≤ |z1|+|z2|
- The results of the multiplication of two complicated numbers and its conjugate worth ought to end in a posh quantity and it is going to be a effective value.

## What is the value of 15i/2+i

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You can use the calculator for any math drawback you would like to solve, like calculating the top at a restaurant, making graphs, or fixing geometry problems.

- Type your equation into the search field on google.com or
- Search for:
`Calculator`

- Value of bodily constants
- Base and consultant conversion

You can graph difficult equations shortly via getting into your purposes into the search box. You can see what a pattern equation seems like here.

Tips

- To plot a number of purposes together, separate the formulation with a comma.
- To discover the position in additional detail, zoom out and in and pan throughout the plane.

Functions you could graph

- 3D graphs (for desktop browsers that help WebGL)

“This position won’t be plotted correctly”

The plotting algorithm detected one in all these:

- Too many asymptotes
- Too many transitions of the position from outlined to undefined regions
- Too many factors on the graph that would not symbolize the present position worth due to excessive volatility

Try to pan or zoom the position to a distinct region.

“Cannot zoom further”

The pan or zoom motion can’t be carried out as a result of of numerical limitations. Try to pan or zoom the position to a special region.

“Cannot pan on this direction”

The pan or zoom motion can’t be carried out due to numerical limitations. Try to pan or zoom the position to a special region.

You can discover geometry formulation and solutions to complicated geometry issues utilizing Google Search.

Open the geometry calculator

- Search Google for a formula, like:
`Area of a circle.`

- In the field that asserts “Enter value,” sort the values you know.
- To calculate a special value, subsequent to “Solve for, ” click on the Down arrow .

Shapes & formulation you may use

- Supported shapes: 2 and three dimensional curved shapes, platonic solids, polygons, prisms, pyramids, quadrilaterals, and triangles.
- Supported formulation and equations: Area, circumference, regulation of sines and cosines, hypotenuse, perimeter, Pythagorean theorem, floor area, and volume.

Examples

`what is the quantity of a cylinder with radius 4cm and peak 8cm`

`formula for a triangle perimeter`

`find the diameter of a sphere whose quantity is 524 gallons`

`a^2+b^2=c^2 calc a=4 b=7 c=?`

If the calculator does not present up once you enter in an equation:

- Make positive your equation is one thing that may be computed. For example, whenever you lookup “
`7*9/0`

,” you won’t see the calculator pop up as a result of dividing by means of zero doesn’t create a value. - If it nonetheless is never displaying up, attempt including
`=`

to the start or finish of your search.

## When graphed, which parabola opens downward?

If someone asks you when graphed, which parabola opens downward? and you don’t know the answer, don’t worry. Because you will soon find the answer when reading our article below. So don’t hesitate to read it now and always to know when graphed, which parabola opens downward?.

Any quantity might be the enter worth of a quadratic function. Therefore the area of any quadratic position is all actual numbers. Because parabolas have a most or a minimal on the vertex, the variability is restricted. Since the vertex of a parabola might be both a most or a minimum, the variability will include all [latex]y[/latex]-values better than or equal to the [latex]y[/latex]-coordinate of the vertex or lower than or equal to the [latex]y[/latex]-coordinate on the turning point, counting on whether or not or not the parabola opens up or down.

A General Note: Domain and Range of a Quadratic Function

The area of any quadratic position is all actual numbers.

The fluctuate of a quadratic position written basically type [latex]f\left(x\right)=a{x}^{2}+bx+c[/latex] with a wonderful [latex]a[/latex] worth is [latex]f\left(x\right)\ge f\left(-\frac{b}{2a}\right)[/latex], or [latex]\left[f\left(-\frac{b}{2a}\right),\infty \right)[/latex]; the variability of a quadratic position written generally variety with a unfavourable [latex]a[/latex] worth is [latex]f\left(x\right)\le f\left(-\frac{b}{2a}\right)[/latex], or [latex]\left(-\infty ,f\left(-\frac{b}{2a}\right)\right][/latex].

The fluctuate of a quadratic position written in common type [latex]f\left(x\right)=a{\left(x-h\right)}^{2}+k[/latex] with a wonderful [latex]a[/latex] worth is [latex]f\left(x\right)\ge k[/latex]; the variability of a quadratic position written in typical type with a damaging [latex]a[/latex] worth is [latex]f\left(x\right)\le k[/latex].

How To: Given a quadratic function, discover the area and range.

- The area of any quadratic position as all actual numbers.
- Determine whether [latex]a[/latex] is effective or negative. If [latex]a[/latex] is positive, the parabola has a minimum. If [latex]a[/latex] is negative, the parabola has a maximum.
- Determine the utmost or minimal worth of the parabola, [latex]k[/latex].
- If the parabola has a minimum, the variability is given via [latex]f\left(x\right)\ge k[/latex], or [latex]\left[k,\infty \right)[/latex]. If the parabola has a maximum, the variability is given by means of [latex]f\left(x\right)\le k[/latex], or [latex]\left(-\infty ,k\right][/latex].

Example: Finding the Domain and Range of a Quadratic Function

Find the area and differ of [latex]f\left(x\right)=-5{x}^{2}+9x – 1[/latex].

As with any quadratic function, the area is all actual numbers or [latex]\left(-\infty,\infty\right)[/latex].

Because [latex]a[/latex] is negative, the parabola opens downward and has a most value. We have to find out the utmost value. We can start via means of discovering the [latex]x[/latex]-value of the vertex.

[latex]h=-\dfrac{b}{2a}=-\dfrac{9}{2\left(-5\right)}=\dfrac{9}{10}[/latex]

The most worth is given by [latex]f\left(h\right)[/latex].

[latex]f\left(\dfrac{9}{10}\right)=5{\left(\dfrac{9}{10}\right)}^{2}+9\left(\dfrac{9}{10}\right)-1=\dfrac{61}{20}[/latex]

The differ is [latex]f\left(x\right)\le \dfrac{61}{20}[/latex], or [latex]\left(-\infty ,\dfrac{61}{20}\right][/latex].

Try It

Find the area and differ of [latex]f\left(x\right)=2{\left(x-\dfrac{4}{7}\right)}^{2}+\dfrac{8}{11}[/latex].

The area is all actual numbers. The differ is [latex]f\left(x\right)\ge \dfrac{8}{11}[/latex], or [latex]\left[\dfrac{8}{11},\infty \right)[/latex].

## Which equation is an example of the commutative property of multiplication?

Has anyone ever asked you which equation is an example of the commutative property of multiplication?? Can you answer that person is question or not? Do you know the answer to that question? If not, then please read the article below. Because this article not only tells you the answer of which equation is an example of the commutative property of multiplication? but also tells you the surrounding things.

The Commutative Property of Subtraction and Division states that the order through which numbers are subtracted or divided doesn’t have an effect on the result of the operation. In different words, subtracting or dividing a quantity by means of one other quantity yields the identical consequence no matter the order by which the numbers are listed.

This belongings is represented utilizing the subsequent symbols:

a – b = b – a

a ÷ b = b ÷ a

For example, take into account the subsequent two equations:

8 – three = three – eight (true)

16 ÷ four = four ÷ sixteen (true)

As you’ll be able to see, in every case, reversing the order of the numbers doesn’t alternate the results of the operation.

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